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Determine the conditional probability P (X>2.5 | X \leq 4) Suppose Z is the standard normal distribution. Illustrate with a sketch and find k such that: P (Z \leqslant k)=0.81 (Z ⩽ k) = 0.81. According to Chebyshev's theorem, the probability that any random variable assumes a value within 3 standard deviations of the mean is at least 8/9.
SOLVED Determine the value k, so that P(Z
Send us Feedback. Free Standard Normal Distribution Calculator - find the probability of Z using standard normal distribution step-by-step.
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Using the p-value to z-score calculator; What is a "Z score" P value to Z-score conversion table Using the p-value to z-score calculator. If you have a p-value statistic for a given set of data and want to convert it to its corresponding Z score this P to Z calculator will help you accomplish that. Simply enter the P-value and choose whether it was computed for a one-tailed or two-tailed.
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Probability with the standard normal table (P(0 to z)) YouTube
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Sal used a simple shortcut. A z table indicates the proportion of the area of the distribution TO THE LEFT of a given z score. Given that normal distributions are by definition symmetric around their means, if we're looking for the area of just one tail in the positives, we can either subtract the proportion given by the z table from 1, or simply look at the corresponding negative z-score.
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To find the value k for P(k < Z) = .0089, we first need to find the complement of the probability, which is P(Z < k) = 1 - .0089 = .9911. Then, we look up the z-score in a standard normal distribution table or use a calculator. In this case, we find that k ≈ 2.36. Step 5/6 5. To find Z..0125, we look up the z-score in a standard normal.
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k~~1.96. We're looking for a bound k such that the area under the standard normal curve between -k and k is 0.95. This means that the tails should have the remaining 0.05 area, and since the tails are symmetric, the upper tail should have area 0.025. And if the upper tail has area 0.025, then the total area not in that upper tail should be the other 0.975.